Brahmagupta’s solution to a quadratic equation of the form ax2 + bx = c involved only one solution. Which solution would he have found for the equation 3x2 + 4x = 6? x = x = x = x =

Respuesta :

Answer:

x = -2.25 or x = 0.92

Step-by-step explanation:

The given equation is 3x² + 4x -6 = 0

Since the equation is in the form of ax² + bx + c = 0

Therefore solution of the equation will be

[tex]x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}=\frac{-4\pm \sqrt{16+72}}{6}[/tex]

[tex]=\frac{-4\pm \sqrt{90}}{6}=\frac{-4\pm 9.49}{6}[/tex]

[tex]x=0.92[/tex] Or [tex]x=-2.25[/tex]

Therefore either x = 0.92 is the answer or x = -2.25 is the answer.

Answer:

it was A

Step-by-step explanation: