The smallest possible inside length of the tank is about 0.507 m
Some units of length and its conversion that need to be recalled are:
[tex]1 ~ foot = 30.48 ~ cm[/tex]
[tex]1 ~ inch = 2.54 ~ cm[/tex]
[tex]1 ~ foot = 12 ~ inches[/tex]
[tex]1 ~ mile = 1609.34 ~ metres[/tex]
[tex]1 ~ yard = 0,9144 ~ metres[/tex]
[tex]1 ~\mu m = 1 \times 10^{-6} ~ m[/tex]
Let us now tackle the problem!
This problem is about conversion of units of volume.
[tex]\boxed {1 ~ L = 1 ~ dm^3 = 1 \times 10^{-3} ~ m^3}[/tex]
[tex]130 ~ L = 130 \times 10^{-3} ~ m^3 = 0,13 ~ m^3[/tex]
To find the length of the tank we can use the following formula.
[tex]\text{Volume of Cube} = (\text{Side Length})^3[/tex]
[tex]\text{Side Length} = \sqrt[3]{\text{Volume of Cube}}[/tex]
[tex]\text{Side Length} = \sqrt[3]{0.13 ~ m^3}[/tex]
[tex]\text{Side Length} \approx 0.507 ~ m[/tex]
Grade: High School
Subject: Physics
Chapter: Physical Quantities
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate , Length , Mass , Physical , Quantities , Conversion , Unit , cg , mg , kg
