Respuesta :
mCuSO4: 64+32+16+4 = 160 g/mol
6,02×10²³ ------- 160g
3,36×10²³ -------- X
X = (160×3,36×10²³)/6,02×10²³
X = 89,3 g
:•)
6,02×10²³ ------- 160g
3,36×10²³ -------- X
X = (160×3,36×10²³)/6,02×10²³
X = 89,3 g
:•)
Answer:
89.02g
Explanation:
First you have to calculate how many grams weighs one mole of CuSO4.
Cu = 63.5g
S = 32g
O = 16 x 4 = 64g
1 mole CuSO4 = 159.5g
Then we have to know that 1 mole is [tex]6.022x10 ^{23}[/tex] molecules.
Now we calculate :
[tex]159.5g=6.022x10^{23} molecules [/tex]
[tex]x=3.36x10^{23} molecules[/tex]
[tex]\frac{3.36x10^{23} x 159.5}{6.022x10^{23}}=89.02g[/tex]