Respuesta :
Let [tex]a_n [/tex] be the n'th term of a sequence,
for example [tex]a_1[/tex] is the first term, [tex]a_2[/tex] is the second term and so on.
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a sequence is arithmetic if the difference between any 2 terms is equal:
so an arithmetic sequence, for the first term = t, and the common difference = d, has the following form:
[tex]a_1=t[/tex]
[tex]a_2=t+d[/tex]
[tex]a_3=t+d+d[/tex]
[tex]a_4=t+d+d+d[/tex]
so clearly [tex]a_n=t+d*(n-1)[/tex]
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A sequence is geometric, if the ratio between any 2 consecutive terms is the same, and it is called the common ratio.
a geometric ratio with first term = t, and common ratio = r is:
[tex]a_1=t[/tex]
[tex]a_2=t*r[/tex]
[tex]a_3=t*r*r[/tex]
[tex]a_4=t*r*r*r[/tex]
thus clearly [tex]a_n=t* r^{n-1} [/tex]
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Part 1:
"Jasmine practices the piano for __30___ minutes on Monday. Every day she ____increases_______ her practice time by ____5 minutes_____. "
let [tex]a_n[/tex] be the number of hours Jasmine practices the n'th day,
for n=7, t=30, d=5 we have
[tex]a_7=30+5*(7-1)=30+5*6=30+30=60[/tex],
minutes is the time Jasmine practices on the 7the day.
Part 2
"Anthony goes to the gym for ___60___ minutes on Monday. Every day he ___increases______his gym time by ____1/10_of the previous day_____. "
if [tex]S_n[/tex] represents the minutes that Anthony goes to gym on the n'th day,
then
[tex]S_1=60[/tex]
[tex]S_2=60+1/10*60=10/10*60+1/10*60=11/10*60=1.1*60[/tex]
[tex]S_3=1.1*1.1*60[/tex]
[tex]S_4=1.1*1.1*1.1*60[/tex]
[tex]S_5=1.1*1.1*1.1*1.1*60= (1.1)^{4}*60= 1.4641*60=87.85[/tex]
(minutes)
Part 3: it is clear that the formula that can be derived in Part 2 is:
[tex]S_n=60*(1.1)^{n-1} [/tex]
so assume we want to find how many hours does Anthony spend in the gym on the 10th day,
then we calculate [tex]S_10=60*(1.1)^{9}=60*2.358=141.5[/tex] (minutes)
for example [tex]a_1[/tex] is the first term, [tex]a_2[/tex] is the second term and so on.
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a sequence is arithmetic if the difference between any 2 terms is equal:
so an arithmetic sequence, for the first term = t, and the common difference = d, has the following form:
[tex]a_1=t[/tex]
[tex]a_2=t+d[/tex]
[tex]a_3=t+d+d[/tex]
[tex]a_4=t+d+d+d[/tex]
so clearly [tex]a_n=t+d*(n-1)[/tex]
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A sequence is geometric, if the ratio between any 2 consecutive terms is the same, and it is called the common ratio.
a geometric ratio with first term = t, and common ratio = r is:
[tex]a_1=t[/tex]
[tex]a_2=t*r[/tex]
[tex]a_3=t*r*r[/tex]
[tex]a_4=t*r*r*r[/tex]
thus clearly [tex]a_n=t* r^{n-1} [/tex]
--------------------------------------------------------------------------------------------------
Part 1:
"Jasmine practices the piano for __30___ minutes on Monday. Every day she ____increases_______ her practice time by ____5 minutes_____. "
let [tex]a_n[/tex] be the number of hours Jasmine practices the n'th day,
for n=7, t=30, d=5 we have
[tex]a_7=30+5*(7-1)=30+5*6=30+30=60[/tex],
minutes is the time Jasmine practices on the 7the day.
Part 2
"Anthony goes to the gym for ___60___ minutes on Monday. Every day he ___increases______his gym time by ____1/10_of the previous day_____. "
if [tex]S_n[/tex] represents the minutes that Anthony goes to gym on the n'th day,
then
[tex]S_1=60[/tex]
[tex]S_2=60+1/10*60=10/10*60+1/10*60=11/10*60=1.1*60[/tex]
[tex]S_3=1.1*1.1*60[/tex]
[tex]S_4=1.1*1.1*1.1*60[/tex]
[tex]S_5=1.1*1.1*1.1*1.1*60= (1.1)^{4}*60= 1.4641*60=87.85[/tex]
(minutes)
Part 3: it is clear that the formula that can be derived in Part 2 is:
[tex]S_n=60*(1.1)^{n-1} [/tex]
so assume we want to find how many hours does Anthony spend in the gym on the 10th day,
then we calculate [tex]S_10=60*(1.1)^{9}=60*2.358=141.5[/tex] (minutes)