Respuesta :

x=2y^2 -8
or
2y^2= x+8
y^2 = (x+8)/2

[tex]y = \sqrt{ \frac{x+8}{2} } [/tex]

we have

[tex]y=2x^{2} -8[/tex]

Step [tex]1[/tex]

Exchanges the variable x for y and the variable y for x

[tex]x=2y^{2} -8[/tex]

Step [tex]2[/tex]

Clear the variable y

[tex]2y^{2}=x+8[/tex]

[tex]y^{2}=\frac{x+8}{2} \\ \\y=(+/-)\sqrt{\frac{x+8}{2}}[/tex]

so

the inverse is equal to-------> [tex]y=(+/-)\sqrt{\frac{x+8}{2}}[/tex]

therefore

the answer is

[tex]y=(+/-)\sqrt{\frac{x+8}{2}}[/tex]