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In the figure, point k is the image of point j under a reflection across line L. Find y

In the figure point k is the image of point j under a reflection across line L Find y class=

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nobillionaireNobley
Since, point K is the image of point J under a reflection across line L.

The distance, JM = MK

Hence, 2x + 4 = 4x - 6
4x - 2x = 4 + 6
2x = 10
x = 5

Also refrection of a point across a line form an angle of 90 degrees at the point of refrection.
i.e. 3y - 30 = 90
3y = 90 + 30 = 120
y = 120 / 3 = 40

Therefore, the value of y is 40.
fichoh

The value of y in the figure given in the question is 40°

The reflection across point L means that the angle formed at point L is 90°

  • Angle formed at point L = 3y - 30

This can be translated to mean ;

  • L = 90°

Hence,

  • (3y - 30)° = 90°

Solving the expression ; (3y - 30)° = 90°

(3y - 30)° = 90°

Collect like terms

3y = 90° + 30°

3y = 120°

Divide both sides by 3

3y/3 = 120°/3

y = 40°

Therefore, the value of y in the figure shown is 40°

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