bugboyz
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I NEED HELP ON THIS BADLY PLEASE!! Im giving lots of points and this is due today so it would help so much if someone can help me with this please! :c

I NEED HELP ON THIS BADLY PLEASE Im giving lots of points and this is due today so it would help so much if someone can help me with this please c class=

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semsee45

Answer:

D) side AB = 7.32

Step-by-step explanation:

The tangent trigonometric ratio is the ratio of the length of the side opposite an angle in a right triangle to the length of the adjacent side:

[tex]\boxed{\begin{array}{l}\underline{\textsf{Tangent trigonometric ratio}}\\\\\sf \tan(\theta)=\dfrac{O}{A}\\\\\textsf{where:}\\\phantom{ww}\bullet\;\textsf{$\theta$ is the angle.}\\\phantom{ww}\bullet\;\textsf{$O$ is the side opposite the angle.}\\\phantom{ww}\bullet\;\textsf{$A$ is the side adjacent the angle.}\end{array}}[/tex]

In the given triangle ABC:

  • θ = 26°
  • O = AB
  • A = 15

Substitute the values into the ratio and solve for AB:

[tex]\tan 26^{\circ}=\dfrac{AB}{15}\\\\\\AB=15\tan 26^{\circ}\\\\\\AB=15\tan 26^{\circ}\\\\\\AB=7.315988828\\\\\\AB=7.32\;\sf(2\;d.p.)[/tex]

Therefore, the missing side length AB is 7.32 units.

msm555

Answer:

Side AB = 7.32

Step-by-step explanation:

To find the length of side [tex]\sf AB [/tex] (the side opposite to angle [tex]\sf C [/tex]) in triangle [tex]\sf ABC [/tex], we can use the trigonometric ratios from trigonometry.

Specifically, we'll use the tangent function, as we have the opposite and adjacent sides.

Given that:

  • [tex]\sf BC = 15 [/tex] (adjacent side)
  • [tex]\sf \angle C = 26^\circ [/tex]

We want to find [tex]\sf AB [/tex].

We can use the tangent function, which is defined as:

[tex]\sf \tan(\theta) = \dfrac{\text{opposite}}{\text{adjacent}} [/tex]

In this case, we have:

[tex]\sf \tan(\angle C) = \dfrac{AB}{BC} [/tex]

Plugging in the known values:

[tex]\sf \tan(26^\circ) = \dfrac{AB}{15} [/tex]

Solve for AB.

[tex]\sf AB = \tan(26^\circ) × 15 [/tex]

Using calculator, we can calculate tan(26°).

[tex]\sf AB = 0.4877 \times 15 [/tex]

[tex]\sf AB = 4877325886 \times 15 [/tex]

[tex]\sf AB \approx 7.315988828 [/tex]

[tex]\sf AB \approx 7.32\textsf{( in 2 d.p.)}[/tex]

So, the missing side length AB of the triangle is:

Side AB = 7.32

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