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How much heat is required to convert 2.18 g of water at 29.0 ∘C to steam at 100.0 ∘C ?

Respuesta :

Answer:

To calculate the heat required to convert water to steam, we can use the formula:

q = m * ΔHvap

where q is the heat required, m is the mass of water, and ΔHvap is the heat of vaporization.

First, let's calculate the mass of water in moles:

moles = mass / molar mass

The molar mass of water is approximately 18.015 g/mol.

Next, we can calculate the heat required using the equation:

q = moles * ΔHvap

The heat of vaporization for water is approximately 40.7 kJ/mol.

Let's plug in the values:

mass = 2.18 g

molar mass = 18.015 g/mol

ΔHvap = 40.7 kJ/mol

Now, we can calculate the heat required.