Explanation: Hi! We must use the Fahrenheit to Kelvin formula to solve this question. We plug in the values and then use a calculator to evaluate it.
Formula: [tex]\boxed{K = \frac{9}{5}(F - 32) + 273.15}[/tex]
Where:
Solving:
[tex]\text{Given temperature } 30^\circ F: \\K = \left(\frac{30 - 32}{9}\right) \times 5 + 273.15 \\K = \frac{-2 \times 5}{9} + 273.15 \\K = \frac{-10}{9} + 273.15 \\ \boxed{\boxed{\\K \approx 272}}[/tex]
That's it!