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In pointers wire hair, S is dominant to smooth show opponent square of cross between a homozygous, wired hair, male dog, with a smooth haired female, what will be the genotype and phenotype ratios of their potential offspring?

Respuesta :

Answer:

The genotypic and phenotypic ratios of the F1 generation in a cross between heterozygous wire-haired dog with a smooth haired dog are 1 Ss: 1Ss and 1 wire haired: 1 smooth haired respectively.

Explanation:

According to this question, a gene coding for hair texture in dogs. Wire hair (S) is dominant to smooth hair (s).

If a heterozygous wire-haired dog (Ss) with a smooth haired dog (ss), the following gametes will be produced by each parent:

Ss- S and s

ss - s and s.

Using these gametes in a punnet square (see attached image), the following genotypic and phenotypic proportion of offsprings will be produced:

Ss - wire haired

Ss - wire haired

ss - smooth haired

ss - smooth haired

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