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PICTURE OF A COIN WITH A HOLE IN THE MIDDLE DIAGRAM OF THE TOP SURFACE OF THE COIN O Diameter of circular coin-32 mm NOTE: O The square hole has an area of 0,9025 cm² The circular coin has an arcan of 8,04 cm² The weight of the coin (mass of the coin) is 28,25 g [Source: www.pinterest.com and www.bin.coin Use the information above and answer the questions that follow 1.2.1 Determine the difference between the area of the circular coin and the square hole area in mm², 1.2.2 Write the square hole area of the coin as a percentage of the circular coin area in. Round the answer to the nearest whole number. (4) ​

Respuesta :

Answer:

Diameter of coin

(

d

)

=

1

m

∴

Radius of coin

(

r

)

=

1

2

=

0.5

m

⇒

Area of

4

sectors

=

4

×

θ

360

o

×

π

r

2

⇒

Area of

4

sectors

=

4

×

90

o

360

o

×

3.14

×

(

0.5

)

2

⇒

Area of

4

sectors

=

0.785

c

m

2

⇒

Side of square

=

0.5

+

0.5

=

1

m

⇒

Area of square

=

(

s

i

d

e

)

2

=

(

1

)

2

=

1

c

m

2

⇒

Area of shaded region = Area of square - Area of

4

sectors.

⇒

Area of shaded region

=

1

−

0.785

=

0.215

c

m