Question 2. Find the length of AP. Given PT = 2.000 in., ET = 1.200 in, PO = 0.614
in., and diameter = 2.620 in. Round the answer to 3 decimal places in inches and
enter the answer inside the box below.

Question 2 Find the length of AP Given PT 2000 in ET 1200 in PO 0614 in and diameter 2620 in Round the answer to 3 decimal places in inches and enter the answer class=

Respuesta :

Question 1:

To find angle POF, we need to apply the tangent-secant angle theorem, which states that the measure of an angle formed by a tangent and a secant intersecting at the point of tangency is equal to half the measure of its intercepted arc.

Given that angle PEO is 46°, we can find angle POF using the intercepted arc PO.

Since angle POF is an inscribed angle intercepting arc PO, we have:

angle POF = 1/2 * arc PO

Since angle PEO is given as 46° and it subtends arc PO, arc PO will be twice this measure, which is 92°.

Now, we can find angle POF:

angle POF = 1/2 * 92°

angle POF = 46°

Therefore, angle POF is 46°.

Question 2:

To find the length of AP, we can use the Pythagorean theorem in triangle APT.

Given:

PT = 2.000 in.

ET = 1.200 in.

PO = 0.614 in.

Diameter = 2.620 in.

We can first find the length of AE using the Pythagorean theorem:

AE^2 = AP^2 + PE^2

AP^2 = AE^2 - PE^2

Given that PO is the radius and the diameter is 2.620 in, we can find the length of AE:

AE = Diameter - PO

AE = 2.620 in - 0.614 in

AE = 2.006 in

Now, we can find the length of AP:

AP^2 = 2.006^2 - 1.200^2

AP^2 = 4.024 - 1.440

AP^2 = 2.584

Taking the square root of both sides to solve for AP:

AP ≈ √2.584

AP ≈ 1.606 in

Therefore, the length of AP is approximately 1.606 inches.