Answer:
Explain it: The correct answer is:
b. \( \frac{31}{3} > \frac{41}{4} < \frac{51}{5} \)
To compare these fractions, it's helpful to find a common denominator. In this case, we can use \( 60 \) as a common denominator.
So, \( \frac{31}{3} \) becomes \( \frac{31 \times 20}{3 \times 20} = \frac{620}{60} \)
\( \frac{41}{4} \) remains the same since \( 4 \) is already a factor of \( 60 \), which gives \( \frac{2460}{60} \)
\( \frac{51}{5} \) becomes \( \frac{51 \times 12}{5 \times 12} = \frac{612}{60} \)
Now, comparing the numerators:
\( 620 > 2460 > 612 \)
So, the correct order is:
\( \frac{31}{3} > \frac{41}{4} < \frac{51}{5} \)
