Respuesta :

Since PQ is parallel to OR, we have angle QPO = angle ROQ because they are alternate angles.

So, angle ROQ = m°.

Also, angle QRO = 2m°.

Since all angles in a triangle add up to 180°, we have:

angle QRO + angle ROQ + angle QOR = 180°

Substituting the given values:

2m + m + angle QOR = 180°

Combining like terms:

3m + angle QOR = 180°

Since angle QOR is an angle at the center of the circle, it is twice the angle at the circumference subtended by the same arc. So, angle QOR = 2 * angle QPO = 2m.

Substituting this into the equation:

3m + 2m = 180°

5m = 180°

Dividing both sides by 5:

m = 180° / 5

m = 36°

So, the value of m is 36°.

Answer:

m = 36

Step-by-step explanation:

Points P, Q, and R lie on the circumference of the circle with center O.

The line segments connecting the center O to points P, Q and R represent the radii of the circle and are therefore of equal length:

[tex]\sf \overline{OP}=\overline{OQ}=\overline{OR}[/tex]

This means that triangles OPQ and OQR are isosceles triangles, since two of their sides are equal in length.

In an isosceles triangle, the angles opposite the congruent sides are equal in measure. Therefore:

  • As OP = OQ in triangle OPQ, then m∠OPQ = m∠PQO = m°.
  • As OQ = OR in triangle OQR, then m∠OQR = m∠QRO = 2m°.

Line segment OQ is the transversal of parallel lines PQ and OR.

According to the Alternate Interior Angle Theorem, m∠ROQ =  m∠PQO.

Since m∠PQO = m°, then m∠ROQ = m°.

Now, we have determined the measures of all three angles of triangle OQR:

  • m∠ROQ = m°
  • m∠OQR = 2m°
  • m∠QRO = 2m°

Since the interior angles of a triangle sum to 180°, then:

[tex]\sf m\angle ROQ + m\angle OQR + m\angle QRO = 180^{\circ}[/tex]

Substitute the expression for each angle into the sum equation and solve for m:

[tex]\sf m^{\circ} + 2m^{\circ} + 2m^{\circ} = 180^{\circ}\\\\\\5m^{\circ} = 180^{\circ}\\\\\\\5m=180\\\\\\\dfrac{5m}{5}=\dfrac{180}{5}\\\\\\m=36[/tex]

Therefore, the value of m is:

[tex]\LARGE\boxed{\boxed{\sf m=36}}[/tex]

Ver imagen semsee45