Respuesta :
Let the variable of the equation be x.
I'm gonna go backwards of the factorization process.
Given,
x = 11 or 3
(x - 11)(x - 3) = 0
x² -3x -11x + 33 = 0
x² -14x + 33 = 0
Hence, f(x) = x² - 14x + 33.
I'm gonna go backwards of the factorization process.
Given,
x = 11 or 3
(x - 11)(x - 3) = 0
x² -3x -11x + 33 = 0
x² -14x + 33 = 0
Hence, f(x) = x² - 14x + 33.
Algebraically speaking, a quadratic function can be written as a product of two binomials, whose form is described below:
[tex]p(x) = \Pi \limits_{i= 1}^{2} (x-r_{i})[/tex] (1)
Where [tex]r_{i}[/tex] is the i-th zero of the quadratic function.
If we know that [tex]r_{1} = 11[/tex] and [tex]r_{2} = 3[/tex], then the quadratic function is:
[tex]p(x) = (x-11)\cdot (x-3)[/tex]
[tex]p(x) = x^{2}-14\cdot x +33[/tex]
The quadratic function whose zeros are 11 and 3 is [tex]p(x) = x^{2}-14\cdot x +33[/tex].
We kindly invite to check this question on quadratic functions: https://brainly.com/question/2263981