Respuesta :

Let the variable of the equation be x.

I'm gonna go backwards of the factorization process.

Given,

x = 11 or 3

(x - 11)(x - 3) = 0

x² -3x -11x + 33 = 0 

x² -14x + 33 = 0 

Hence, f(x) = x² - 14x + 33.

Algebraically speaking, a quadratic function can be written as a product of two binomials, whose form is described below:

[tex]p(x) = \Pi \limits_{i= 1}^{2} (x-r_{i})[/tex] (1)

Where [tex]r_{i}[/tex] is the i-th zero of the quadratic function.

If we know that [tex]r_{1} = 11[/tex] and [tex]r_{2} = 3[/tex], then the quadratic function is:

[tex]p(x) = (x-11)\cdot (x-3)[/tex]

[tex]p(x) = x^{2}-14\cdot x +33[/tex]

The quadratic function whose zeros are 11 and 3 is [tex]p(x) = x^{2}-14\cdot x +33[/tex].

We kindly invite to check this question on quadratic functions: https://brainly.com/question/2263981