Answer:
The correct choice that represents these zeros is not provided in the options.
Step-by-step explanation:
To find the zeros of the quadratic function \( f(x) = 3x^2 + 11x - 4 \), we need to set the function equal to zero and solve for \( x \). The zeros of a function are the values of \( x \) that make the function equal to zero.
1. Set the function equal to zero:
\( 3x^2 + 11x - 4 = 0 \)
2. Factor the quadratic equation or use the quadratic formula to solve for \( x \):
The factored form of the quadratic equation can be written as:
\( (3x - 1)(x + 4) = 0 \)
3. Find the zeros by setting each factor equal to zero:
\( 3x - 1 = 0 \) and \( x + 4 = 0 \)
Solving these equations gives:
\( 3x = 1 \) → \( x = \frac{1}{3} \)
\( x = -4 \)
Therefore, the zeros of the quadratic function \( f(x) = 3x^2 + 11x - 4 \) are \( x = \frac{1}{3} \) and \( x = -4 \). The correct choice that represents these zeros is not provided in the options.