11.73375 grams of kcl present in 75.0 ml of 2.10 m kcl.
Calculation,
Given data,
Volume (V) = 75 mL = 0.075 L
Concentration (C) = 2.1M
C = n/V
n = C×V
n = 2.1×0.075
n = 0.1575 mol
Where, n = number of moles.
Let mass of the KCl be X g.
Given molar mass of KCl =39+35.5 = 74.5 g/mol
1 mol contains 74.5g of KCl
0.1575 mol contains 74.5×0.1575 grams of KCl.
Mass of KCl (X) = 11.73375 g KCl
The 6.022×1023 of chemical species like an electrons, molecules, ions etc is called moles .
To learn more about moles here.
https://brainly.com/question/26416088
#SPJ3
