[tex]\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 4\%\to \frac{4}{100}\to &0.04\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{twice, thus}
\end{array}\to &2\\
t=years\to &5
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.04}{2}\right)^{2\cdot 5}[/tex]
