For which of the following values of b will the equation 4x²+bx+7=0 have real solutions?
(1) b=5
(2) b=9
(3) b=-8
(4) b=-11

Respuesta :

anbu40

Answer:

b = -11

Step-by-step explanation:

 4x² + bx + 7 = 0

a = 4 ; b = b ; c = 7

If the discriminant is greater than zero, then the quadratic equation will have a real solution.

 D = b² - 4ac

    = b² - 4 * 4 *7

    = b² - 112

b² - 112 > 0

        b² > 112

From the given options, b = -11 satisfies the above condition.

(-11)² > 112

121 > 112

Answer: b = -11

Option 1) b = 5, b² = 25

               25 is less than 112.

Option2) b = 9; b² = 9² = 81

               81 is less than 112.

Option 3) b = (-8) ; b² = (-8)² = 64

               64 is less than 112.