A man wishes to get from an initial point on the corner of a square lake to the terminal point on the opposite corner of the lake (diagonally across). Each side to the lake is exactly 2 miles long. If he walks 4 mph and swims 2 mph what is the minimum time for the trip?

Respuesta :

Answer:

  1 hour

Step-by-step explanation:

You want the shortest time required to get between opposite corners of a 2 mile square lake if the man walks at 4 mph and swims at 2 mph.

Time

The land distance around two sides of the lake is 2+2 = 4 miles. At a walking speed of 4 mph, walking the entire distance would take ...

  time = distance/speed

  time = (4 mi)/(4 mi/h) = 1 h

The shortest distance across the lake that the man could swim is 2 miles (the length of one side). At 2 mph, that would take ...

  (2 mi)/(2 mi/h) = 1 h

After having swum 2 miles, the man would still have some distance to walk. The total time involving any swimming would be more than 1 hour.

Walking the whole distance takes the shortest time.

The minimum time for the trip is 1 hour.

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Additional comment

If swimming is involved, the shortest time would be about 1.366 hours. That is the time for the path leaving at an angle of 30° from the shore.