mhauser18 mhauser18

24-03-2024
Chemistry

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How many particles would there be in 26.7 grams of Na2O?

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jsimpson11000 jsimpson11000

24-03-2024

Answer:

Explanation:

Mole weight of Na2 0 = (2 * 22.989 + 15.999) = 61.977 g/mole

26.7 g / 61.977 g/mole = .4308 moles

ech mole has 6.022 x 10^23 particles

6.022 x 10^23 parts/mole * .4308 mole = 2.59 x 10^23 particles

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