contestada

4. If 14.7g of calcium is placed in 11.5g of water, what mass of hydrogen gas is produced?

Respuesta :

1. We balance the chemical equation:
Calcium (Ca) + Water (H₂O) → Calcium Hydroxide (Ca(OH)₂) + Hydrogen Gas (H₂)

2. Calculate moles of calcium:
Moles of calcium = Mass of calcium / Molar mass of calcium
Moles of calcium = 14.7g / 40.08g/mol ≈ 0.366 moles

3. Moles of hydrogen gas produced equals moles of calcium, as per the balanced equation:
Moles of hydrogen gas = 0.366 moles

4. Find mass of hydrogen gas using the molar mass of hydrogen gas:
Mass of hydrogen gas = Moles of hydrogen gas * Molar mass of hydrogen gas
Mass of hydrogen gas = 0.366 moles * 2.016g/mol ≈ 0.739g

Therefore, approximately 0.739 grams of hydrogen gas is produced.