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A bacterial culture starts with 560 bacteria cells. Three days later, it has 705
bacteria cells. About how many bacteria will be present 10 days after the
start? Use the equation N₁ = Nect where t-time in days and c= growth
factor.
First, solve for c and round to the thousandths:
C=
About
bacteria will be present after 10 days.
(round to the nearest whole bacteria)

A bacterial culture starts with 560 bacteria cells Three days later it has 705 bacteria cells About how many bacteria will be present 10 days after the start Us class=

Respuesta :

mathstudent55

Answer:

1206

Step-by-step explanation:

N_t = N_0 × e^ct

For t = 3 days,

N_3 = N_0 × e^3c

Given:

t = 3

N_0 = 560

N_3 = 705

705 = 560 × e^3c

e^3c = 705/560

ln (e^3c) = ln (705/560)

3c = ln (705/560)

c = [ln (705/560)]/3

c = 0.0767537

N_t = 560 × e^(0.0767537t)

For t = 10,

N_10 = 560 × e^0.767537

N_10 = 1206

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