200g disk with a 8.00 cm diameter rotates about an axis through its center with 0.21 J of kinetic energy
what is the speed of a point on the rim

Respuesta :

Answer:

2.05 m/s

Explanation:

Rotational kinetic energy is:

RE = ½ Iω²

Moment of inertia of a solid disk is I = ½ mr²:

RE = ½ (½ mr²) ω²

RE = ¼ mr²ω²

The tangential speed is v = ωr:

RE = ¼ mv²

Plug in values and solve:

0.21 J = ¼ (0.200 kg) v²

v = 2.05 m/s