Answer:
They are 28 and
Step-by-step explanation:
To solve this problem, we need to set up a system of equations based on the information provided.
Let x be one number and y be another number.
According to the problem:
1. \(x = \frac{y}{2} + 12\)
2. \(x + y = 60\)
Now, we can substitute the expression for x from the first equation into the second equation:
\(\frac{y}{2} + 12 + y = 60\)
Combining like terms:
\(\frac{y}{2} + y + 12 = 60\)
\(\frac{3y}{2} + 12 = 60\)
\(\frac{3y}{2} = 48\)
\(3y = 96\)
\(y = 32\)
Now, we can substitute the value of y back into the first equation to find x:
\(x = \frac{32}{2} + 12\)
\(x = 16 + 12\)
\(x = 28\)
Therefore, the two numbers are 28 and 32.
