Answer:
To solve the equation p^2 - 22p + 121 = 0 for p, we can use the quadratic formula: 1. Identify the coefficients of the equation: a = 1 (coefficient of p^2), b = -22 (coefficient of p), c = 121. 2. Substitute the values of a, b, and c into the quadratic formula: p = (-b ± √(b^2 - 4ac)) / 2a. 3. Calculate the discriminant (b^2 - 4ac) to determine the nature of the solutions: Discriminant = (-22)^2 - 4*1*121 = 484 - 484 = 0. 4. Since the discriminant is 0, the equation has equal real roots. 5. Substitute the values of a, b, and the discriminant into the quadratic formula: p = (-(-22) ± √0) / 2*1 p = (22 ± 0) / 2 p = 22 / 2 p = 11. Therefore, the solution to the equation p^2 - 22p + 121 = 0 is p = 11
