PLEASE HELP!!!!

Quadrilateral ABCD is inscribed in a circle. If angle A=41 and angle D=94, what is the measure of angle C?

Since the quadrilateral is inscribed, its points must be on the circumference of the circle. This means that for any quadrilateral with two fixed angles, the other two must be fixed as well. If we draw both angles A and D accurately, extending their non-common ray sides to the circumference will give us points B and C. From there, we can connect B and C and measure the resulting angles using a protractor. Doing this gives us:

C = 139°

We can also solve for C algebraically using the Inscribed Quadrilateral Theorem, which states that opposite interior angles are supplementary. Thus:

A + C = 180°

41° + C = 180°

C = 139°

reinhard10158 reinhard10158 · Answer 2 · 2024-03-25T23:09:47+01:00

Answer:

angle C = 139°

Step-by-step explanation:

this is a cyclic quadrilateral, as it has all 4 vertexes on the circumscribing circle.

there is a special rule for this :

opposing angles of such a cyclic quadrilateral are acting supplementary angles (together they have 180°).

that means :

angle A + angle C = 180

41 + angle C = 180

angle C = 180 - 41 = 139°

FYI

the same for the other 2 angles:

angle B + angle D = 180

angle B + 94 = 180

angle B = 180 - 94 = 86°

PLEASE HELP!!!!Quadrilateral ABCD is inscribed in a circle. If angle A=41 and angle D=94, what is the measure of angle C?​

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PLEASE HELP!!!!

Quadrilateral ABCD is inscribed in a circle. If angle A=41 and angle D=94, what is the measure of angle C?