A lab group's data whose calculation of the specific heat of iron to be 0.383 J/g°C, 0.382 J/g°C and 0.383 J/g°C in three separate trials. Using accurate and precise give an explanation of their results.

3. What was the energy change of a 32.4g piece of granite, if its temperature decreased from 50.8°C to 39.6°C?

Accurate: The results are accurate because they are close to the accepted value for the specific heat of iron, which is 0.45 J/g°C. The percent error for each trial is:

* Trial 1: (0.383 J/g°C - 0.45 J/g°C) / 0.45 J/g°C * 100% = -14.9%

* Trial 2: (0.382 J/g°C - 0.45 J/g°C) / 0.45 J/g°C * 100% = -15.1%

* Trial 3: (0.383 J/g°C - 0.45 J/g°C) / 0.45 J/g°C * 100% = -14.9%

Precise: The results are precise because they are consistent with each other. The difference between the highest and lowest values is only 0.001 J/g°C.

Energy Change of Granite

The energy change of the granite can be calculated using the following equation:

Q = mcΔt

where:

* Q is the energy change in joules

* m is the mass of the granite in grams

* c is the specific heat of granite in J/g°C

* Δt is the change in temperature in °C

In this case, we have:

* m = 32.4 g

* c = 0.803 J/g°C (assuming granite has a similar specific heat to quartz)

* Δt = 50.8°C - 39.6°C = 11.2°C

Plugging these values into the equation, we get:

Q = (32.4 g) * (0.803 J/g°C) * (11.2°C) = 299.2 J

Therefore, the energy change of the granite is -299.2 J. The negative sign indicates that the granite lost energy as its temperature decreased.