Respuesta :

chowchow4now
So if you subtract the 0 out from the left side, the equation is now [tex]x^{2}-3x=0 [/tex]. Since a x is common in both of the terms on the left side, you can factor it out, now making the equation look like [tex]x(x-3)=0[/tex]. When factoring, each of the separate things (x and (x-3)), must equal zero while the other one doesn't matter. So in order for the equation to be 0, the only potential options for x is 0 and 3. Therefore x=0 and x=3 are the two solutions
apologiabiology
sinc 0=0 then  the equation becomes
x^2-3x=0
factor out x from both terms using revers distributive (ab+ac=a(b+c))
(x)(x-3)=0
if yz=0 then assume that x and/or y=0 so
x=0 and
x-3=0


x=0



x-3=0
add 3 to both sides
x=3

x=3 or 0

Otras preguntas