An open box with a square base is to be constructed from 84 square inches of material. The height of the box is 2 inches. What are the dimensions of the box? (Hint: The surface area is S = x^2 + 4xh.)

The dimension of the box will be 2in by 6in by 6in
The total surface area is the sum of all the surfaces of the given box. Given the surface area of the box expressed as;
S = x^2 + 4xh
Given the following
S = 84 in²
h =2in
Substitute
84 = x^2 + 4(2)x
84 = x^2 + 8x
x^2 + 8x - 84 = 0
Factorize
x^2 +8x - 84 = 0
x^2 + 14x -6x - 84 = 0
x(x+14)-6(x+14) = 0
x = 6in
Find the dimensions
The dimension of the box will be 2in by 6in by 6in
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