When aluminum oxidizes in air, it forms aluminum oxide (ai2o3): 4ai (s) + o2 (g_ -> 2ai2o3 (s) if a 77 g sheet of aluminum oxide formed completely in excess oxygen, how many grams of aluminum were oxidized?

Respuesta :

40,76 g of aluminum where oxidized and the formula should be:
4 Al + 3 O2 → Al2O3

the answer is 41 g

Hope this helps :)