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You are provided with 2.80 mol of nitrogen monoxide gas. using the balanced chemical equation completed in part a, determine how many moles of oxygen gas are needed to completely react with the nitrogen monoxide gas, and how many moles of nitrogen dioxide are formed as a result?

Respuesta :

1mo le Of No= 0.5mole of o2 then 2.8moles of No=1.4moles of o2
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Answer:

1.40 moles of O₂, and 2.80 moles of NO₂

Explanation:

The balanced reaction of nitrogen monoxide (NO) with oxygen (O₂) is:

2NO(g) + O₂(g) → 2NO₂(g)

We can notice that the stoichiometry is 2 moles of NO: 1 mole of O₂: 2 moles of NO₂, thus, for 2.80 mol of NO:

2 moles of NO ------------------- 1 mol of O₂

2.80 moles      ------------------- x

By a simple direct three rule:

2x = 2.80

x = 1.40 moles of O₂

2 moles of NO ----------------- 2 moles of NO₂

2.80 moles      ------------------ y

By a simple direct three rule:

y = 2.80 moles of NO₂.

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