Respuesta :
Answer: [tex]y=\dfrac{-1}{2}(x-2)[/tex]
Step-by-step explanation:
The equation of a line passing through points (a,b) and (c,d) is given by :-
[tex](y-b)=\dfrac{d-b}{c-a}(x-a)[/tex]
Given : The points from which line is passing : (-6,4) and (2,0)
Then , the equation of the line, in point slope form, that passes through (-6,4) and (2,0)will be :-
[tex](y-(0))=\dfrac{4-0}{-6-2}(x-2)\\\\\Rightarrow\y=\dfrac{4}{-8}(x-2)\\\\\Rightarrow\ y=\dfrac{-1}{2}(x-2)[/tex]