Let h = maximum height that a person can jump.
Let v = vertical take off speed.
Ignore air resistance, and g = acceleration due to gravity.
At maximum height, the vertical velocity is zero. Therefore
v² - 2gh = 0
[tex]h= \sqrt{ \frac{v^{2}}{2g} } [/tex]
On the moon, g is 1/6 that on earth. Therefore on the moon, the height is
[tex]h_{moon}= \sqrt{ \frac{6v^{2}}{2g} } = \sqrt{6} h=2.45h[/tex]
Answer:
The factor is 2.45. The height on the moon is 2.45 times that on earth.
