Respuesta :
Refer to the diagram below, which provides a plan view of the problem
Because each player applies the same force, F, the angle between the force and the direction of motion is (1/2)*25° = 12.5°.
Because the sled moves with constant velocity, the sled is in dynamic equilibrium, and
2F cos(12.5°) = 1140 N
1.9526 F = 1140
F = 583.84 N
Answer: 583.8 N (nearest tenth)
Because each player applies the same force, F, the angle between the force and the direction of motion is (1/2)*25° = 12.5°.
Because the sled moves with constant velocity, the sled is in dynamic equilibrium, and
2F cos(12.5°) = 1140 N
1.9526 F = 1140
F = 583.84 N
Answer: 583.8 N (nearest tenth)
Friction force Force that resists the slidihng or rolliong of one side object over another.As both the players pull with the same force therefore each player pull to drag the coach with force of 583.84 N.
Given-
Friction forceon the given sled is 1140 N.
Angle between the two ropes dragging by the players is 25 degree.
What is friction force?
Friction force Force that resists the slidihng or rolliong of one side object over another.
Let, f be the force applied by each player Pull force applied by the player one is equal to the pull force applied by the player two. Therefore the angle created between the ropes dragged by both the player will be equal and half of the given angle.
Angle created by each player with sled is,
[tex]A=\dfrac{25^{\circ}}{2}[/tex]
[tex]A=12.5 ^{\circ}}[/tex]
To keep this sled in dynamic equilibrium the force applied by both the player must be equal to the friction force on the sled in opposite direction. Therefore,
[tex]f\times cos(A) +f \times cos(A) = 1140N[/tex]
[tex]2f\times cos(A) = 1140N[/tex]
[tex]f\times cos(12.5)= \dfrac{1140N}{2}[/tex]
[tex]f\times 0.9763=570[/tex]
[tex]f =\dfrac{570}{0.9763}[/tex]
[tex]f=583.84[/tex]
Hence, each player pull to drag the coach with force of 583.84 N.
Form more about the force, follow the link below-
https://brainly.com/question/4456579
