Respuesta :
solve with subsitution avoiding fractions
2x+6y=7
6x+18y=24
if we solve for x in first, we get x=-3y+7/2, has fractions so no
if we solve for y in first, we get y=-x/3+7/6, has fractions so no
if we solve for x in the 2nd, we get x=-3y+4, no fractions so yay
if we solve for y in the 2nd, we get y=-x/3+4/3, has fractions so no
answer is C
2x+6y=7
6x+18y=24
if we solve for x in first, we get x=-3y+7/2, has fractions so no
if we solve for y in first, we get y=-x/3+7/6, has fractions so no
if we solve for x in the 2nd, we get x=-3y+4, no fractions so yay
if we solve for y in the 2nd, we get y=-x/3+4/3, has fractions so no
answer is C
Well, it says to avoid fractions. So I did the math:
Solving for x in the first equation get you: [tex]x= \frac{7}{2}-3y [/tex]
Solving for y in the first equation gets you:[tex]y= \frac{7}{6} - \frac{2}{6}x [/tex]
Solving for x in the second equation gets you: [tex]x=4-3y[/tex]
Solving for y in the second equation gets you:[tex]y= \frac{24}{18} - \frac{6}{18}x [/tex]
If you look you can see the only option that does not give you fractions is if you solve for x in the second equation. So your answer is c! I hope this helps! =)
Solving for x in the first equation get you: [tex]x= \frac{7}{2}-3y [/tex]
Solving for y in the first equation gets you:[tex]y= \frac{7}{6} - \frac{2}{6}x [/tex]
Solving for x in the second equation gets you: [tex]x=4-3y[/tex]
Solving for y in the second equation gets you:[tex]y= \frac{24}{18} - \frac{6}{18}x [/tex]
If you look you can see the only option that does not give you fractions is if you solve for x in the second equation. So your answer is c! I hope this helps! =)