Let the average profit or loss in year 2006 be x millions,
The average profit for the 8-year period, is the total sum of the profits (or losses) of each year, divided by 8:
so we have:
[tex]\displaystyle{ \frac{3.40+2.10+x+0.60+2.10+0.20+1.30+0.75}{8}=1 [/tex]
[tex]\displaystyle{\frac{10.45+x}{8}=1 [/tex]
[tex]10.45+x=8[/tex]
x=8-10.45=-2.45
Answer: the loss in 2006, was 2.45 million dollars