The perimeter of a rectangle is 24 feet. The length is 3 feet less than twice the width. Which of the following systems would be used to solve this problem ???

The perimeter of a rectangle is 24 feet The length is 3 feet less than twice the width Which of the following systems would be used to solve this problem class=

Respuesta :

Alright, since the perimeter, by definition, is 2l+2w=24 in this case, we have to have that. In addition twice the width=2*width=2w, so 2w-3=l.

The system of equations are  24 = 2(l + w) and l = 2w - 3 option third is correct.

What is the area of the rectangle?

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

Let l be the length and w be the width of the rectangle

By the formula of perimeter:

24 = 2(l + w)

l = 2w - 3 (The length is 3 feet less than twice the width)

The system of equations:

24 = 2(l + w)

l = 2w - 3

Thus, the system of equations are  24 = 2(l + w) and l = 2w - 3 option third is correct.

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