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Mr. Abernathy bought a selection of wrenches for his shop and paid $78. He bought the same number of $1.50 and $2.50 wrenches, and half of that number of $4 wrenches. The number of $3 wrenches is one more than the number of $4 wrenches. How many of each did he buy?

Respuesta :

If the amount of $1.50 wrenches he buys is x, then 1.5x is the amount he pays for $1.50 wrenches since he pays another $1.50 for each wrench he buys of that cost. In addition he buys x amount of $2.50 wrenches, x/2 of 4$ wrenches (since x/2= half of x), and (x/2)+1 is the amount of 3$ wrenches. Adding them all up, we get 1.5x+2.5x+4(x/2)+3(x/2+1)=total cost=78. Since 4/2=2 and 3/2=1.5, we can add these up to get 4x+2x+1.5x+3=7.5x+3=78. Subtracting 3 from both sides, we get 7.5x=75 and by dividing both sides by 7.5, we get x=10. Therefore, Mr. Abernathy buys 10 $1.50 wrenches, 10 $2.50 wrenches, 10/2=5 $4 wrenches, and 5+1=6 3$ wrenches

The number of wrenches is 10 for which he paid $1.50, and $2.50. the number of wrenches is 5 for which he paid $4, and the number of wrenches is 6 for which he paid $3.

What is a linear equation?

It is defined as the relation between two variables if we plot the graph of the linear equation we will get a straight line.

If in the linear equation one variable is present then the equation is known as the linear equation in one variable.

We have:

Mr. Abernathy bought a selection of wrenches for his shop and paid $78.

Let's suppose:

The number of $1.50 wrenches is x

The number of $2.50 wrenches is also x

The number of $4 wrenches is x/2

The number of $3 wrenches is 1+x/2

Then linear equation becomes:

[tex]\rm 1.50x+2.50x+\frac{4x}{2} +3(1+\frac{x}{2} ) = 78[/tex]

[tex]\rm 3x+5x+4x +3(2+x ) = 156[/tex]

15x = 150

x = 10

The value of x = 10

=x/2 ⇒ 10/ 2 ⇒ 5

= 1+x/2 ⇒ 1+5 ⇒ 6

Thus, the number of wrenches is 10 for which he paid $1.50, and $2.50. the number of wrenches is 5 for which he paid $4, and the number of wrenches is 6 for which he paid $3.

Learn more about the linear equation here:

brainly.com/question/11897796

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