The angles in transverse parallel lines are related through some theorems such as vertical angles, corresponding angles, etc. the measure of [tex]\angle 2[/tex] is [tex]50^o[/tex]
Given the attached diagram
First, we solve for x using the corresponding angle theorem
[tex]5x + 55 = 2x + 100[/tex] ---- corresponding angles are equal
Collect like terms
[tex]5x - 2x = 100 - 55[/tex]
[tex]3x = 45[/tex]
Divide both sides by 3
[tex]x = 15[/tex]
We then solve for [tex]\angle 2[/tex] using the straight line theorem
[tex]\angle 2 + 5x + 55 = 180[/tex] ---- sum of angles on a straight line
Substitute 15 for x
[tex]\angle 2 + 5 \times 15 + 55 = 180[/tex]
[tex]\angle 2 + 75 + 55 = 180[/tex]
Collect like terms
[tex]\angle 2 =- 75 - 55 + 180[/tex]
[tex]\angle 2 =50[/tex]
Hence, the measure of [tex]\angle 2[/tex] is [tex]50^o[/tex]
Read more about parallel lines and corresponding angles at:
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