[tex]\bf \begin{array}{llll}
\sqrt{17}\\\\
\sqrt{101}
\end{array}\impliedby \textit{17 and 10 are both prime numbers}
\\\\\\
\sqrt{36}\implies \sqrt{6^2}\implies \pm 6
\\\\\\
\sqrt{50}\implies \sqrt{25\cdot 2}\implies \sqrt{5^2\cdot 2}\implies 5\sqrt{2}\impliedby \textit{2 is a prime number}[/tex]
if a number is a prime number, it has no two equal factors that can produce a product of such a number, and therefore such value is an irrational number.
now, the last one, 5 is being multiplied by an irrational, and therefore the product will yield the same irrational, just a bit larger.
so, the only rational there is the ±6 really.
