Respuesta :
Let
x = the number of shorts bought
y = the number of t-shirts bought
A pair of shorts costs $16 and a t-shirt costs $10. Brandom has $100 to spend.
Therefore
16x + 10y ≤ 100
This may be written as
y ≤ - 1.6x + 10 (1)
Brandon wants at least 2 pairs of shorts. Therefore
x ≥ 2 (2)
Graph the equations y = -1.6x + 10 and x = 2.
The shaded region satisfies both inequalities.
Answer:
Two possible solutions are
(a) 3 pairs of shorts and 4 t-shirts,
(b) 4 pairs of shorts and 2 t-shirts.
x = the number of shorts bought
y = the number of t-shirts bought
A pair of shorts costs $16 and a t-shirt costs $10. Brandom has $100 to spend.
Therefore
16x + 10y ≤ 100
This may be written as
y ≤ - 1.6x + 10 (1)
Brandon wants at least 2 pairs of shorts. Therefore
x ≥ 2 (2)
Graph the equations y = -1.6x + 10 and x = 2.
The shaded region satisfies both inequalities.
Answer:
Two possible solutions are
(a) 3 pairs of shorts and 4 t-shirts,
(b) 4 pairs of shorts and 2 t-shirts.

Two possible solutions are (a) [tex]3[/tex] pairs of shorts and [tex]5[/tex] t-shirts
(b) [tex]4[/tex] pairs of shorts and [tex]3[/tex] t-shirts.
[tex]x=the\; number\; of shorts\\y=the\; number\; of\ t-shirt\; bought[/tex]
So equation formed is
[tex]16x+10y\leq 100[/tex]
[tex]10y\leq 100-16x\\y\leq 10-1.6x[/tex]---Eq [tex]1[/tex]
Bradon wants at least [tex]2[/tex] pair of shorts.Therefore
[tex]x\geq 2[/tex]--Eq [tex]2[/tex]
Now put,
[tex]x=3 \\y=10-1.6(3)\\y=10-4.8\\y=5\\[/tex]
Hence [tex]3[/tex] shorts and [tex]5[/tex] t-shirts
Now put,
[tex]x=4 \\y=10-1.6(4)\\y=10-6.4\\y=3\\[/tex]
Now graph the equation,
Learn more about inequalities here:
https://brainly.com/question/15137133?referrer=searchResults
