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A student earned grades of C,A,B, and A. Those courses had these corresponding credit hours: 4,6,1, and 6. The grading system assigns quality points to letter grades as follows: A=4, B=3, C=2, D=1, and F=0. Compute the grade point average (GPA) and round the result to two decimal places.

Respuesta :

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first 4 credit class earns a C is worth:
4(2)= 8
second 6 credit class earns a A is worth:
6(4) = 24
third 1 credit class earns a B is worth:
1(3) = 3
fourth 6 credit class earns a A is worth:
6(4) = 24

add up the total points
8+24+3+24=59
add up total credits
4+6+1+6=17

divide total points by total credits
59/17 = 3.47 GPA

To calculate GPA we will find the total points of the student and the total credit hours of the student.

The grades point average (GPA) of the student is 3.47.

Given to us

  • A student earned grades of C, A, B, and A.
  • and the corresponding credit hours: 4,6,1, and 6.
  • The grading system assigns quality points to letter grades as follows: A=4, B=3, C=2, D=1, and F=0.

Total points of the students

Points of the students = earned grades x corresponding credit hours

  • For C = 4 x 2 = 8 points
  • For A = 6 x 4 = 24 points
  • For B = 1 x 3 = 3 points
  • For A = 6 x 4 = 24 points

Total points = 8 +24 + 3 + 24 = 59

Total Credit hours

Total Credit hours = 4 + 6 + 1 + 6 = 17 hours

Grade point Average (GPA)

[tex]\rm{Grade\ point\ average\ (GPA) = \dfrac{Total\ points\ of\ the\ students}{Total\ Credit\ hours}[/tex][tex]\rm{Grade\ point\ average\ (GPA) = \dfrac{59\ points}{17\ hours} = 3.47[/tex]

Hence, the grade point average (GPA) of the student is 3.47.

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