Answer:
[tex]5.969\times 10^{20} atoms[/tex] are present in a modern penny.
Explanation:
Mass of copper in modern penny = 0.063 g
Moles of copper : n
[tex]n=\frac{0.063 g}{63.55 g/mol}=0.0009913 mole[/tex]
Number of copper atoms in 0.0009913 mole = n
[tex]N=n\times N_A[/tex]
[tex]N=0.0009913 mol\times 6.022\times 10^{23} mol^{-1}=5.969\times 10^{20} atoms[/tex]
There are 5.97×10²⁰ atoms of copper in the penny.
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms.
This implies that 1 mole of copper, Cu contains 6.02×10²³ atoms.
Recall:
1 mole of copper = 63.55 g
Thus,
Finally, we shall determine the number of atoms present in 0.063 g of copper, Cu. This can be obtained as follow:
63.55 g of Cu = 6.02×10²³ atoms
Therefore,
0.063 g of Cu = 0.063 × 6.02×10²³ / 63.55
Thus, 0.063 g of Cu contains 5.97×10²⁰ atoms
Therefore, we can conclude that there are 5.97×10²⁰ atoms of copper in the penny.
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