There are 8 toppings.
The probability of getting a particular topping is p = 1/8.
The probability of not getting a particular topping is q = 1-p = 7/8.
Note that ₈C₂ = 28
The probability of getting 2 toppings is
[tex]_{8}C_{2} \,p^{2}q^{6} = \frac{8!}{2!6!} ( \frac{1}{8})^{2}( \frac{7}{8})^{6} = 0.1963[/tex]
Answer: 0.1963