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PLEASE ANSWER: Write the equation of the line that passes through the point (-3,-5) and is perpendicular to y=-3x+5

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We are starting with y = 3x -5 which is the slope intercept form (y = mx +b) of a linear equation where the slope is m and the y intercept is b.  In this equation the slope m = 3 A perpendicular line would have a slope that is the negative reciprocal so the slope of the perpendicular line would be m = -1/3 So we have a slope m = -1/3   and a point (3,2)  so use the point slope formula (Y-Y1) = m(X-X1)In this case (X1,Y1) = (3,2) (Y - 2) = (-1/3)(X-3) Y-2 = (-1/3)X + 1 Y = (-1/3)X + 3 would be the equation of the perpendicular line through (3,2)
texaschic101
y = -3x + 5...slope here is -3. A perpendicular line will have a negative reciprocal slope. All thet means is flip the slope and change the sign. So our perpendicular line will have a slope of 1/3....see how I flipped -3, or  -3/1, and made it -1/3...and then switched the sign, making it 1/3)

y = mx + b
slope(m) = 1/3
(-3,-5)...x = -3 and y = -5
sub and find b, the y int
-5 = 1/3(-3) + b
-5 = -1 + b
-5 + 1 = b
-4 = b

so ur perpendicular equation is : y = 1/3x - 4

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