Answer:
B. [tex]8\sqrt2+2\sqrt{10}[/tex] units
Step-by-step explanation:
We are given that a parallelogram PQRS in which point P(-2,5), Q(2,1),R(1,-2) and S(-3,2).
We have to find the perimeter of parallelogram PQRS.
Distance formula : [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Using the formula
[tex]SR=\sqrt{(1+3)^2+(-2-2)^2}=4\sqrt2[/tex]units
[tex]QR=\sqrt{(1-2)^2+(-2-1)^2}=\sqrt{10} units[/tex]
Now, the perimeter of parallelogram =2(SR+QR)
The perimeter of parallelogram =[tex]2(4\sqrt2+\sqrt{10})=8\sqrt2+2\sqrt{10} units[/tex]
Answer:B. [tex]8\sqrt2+2\sqrt{10}[/tex] units
