Answer:
10 calories
Explanation:
The thermal energy needed to increase the temperature of a substance is given by
[tex]Q=m C \Delta T[/tex]
where
m is the mass of the substance
C is the specific heat of the substance
[tex]\Delta T[/tex] is the increase in temperature
In this problem, the mass of the ice is m=20 g, the specific heat is C=0.5 calories/gram°C, and the increase in temperature is [tex]\Delta T=1^{\circ}[/tex]. Therefore, the energy required is
[tex]Q=(20 g)(0.5 cal/g^{\circ}C)(1^{\circ}C)=10 cal[/tex]
