An aluminum sample has a mass of 80.01 g and a density of 2.70 g/cm3. According to the data, to what number of significant figures should the calculated volume of the aluminum sample be expressed?

Not 100% sure, but I'd have to say this:

When rounding for sig figs, you look at the other numbers in your calculation and see which one has the least amount of sig figs. This number is 2.70. (3 sig figs). So, you round to 3 significant figures in your calculation.

Hope this helped!

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Alleei Alleei · Answer 2 · 2019-10-21T18:51:07+02:00

Answer : The volume of aluminium sample should be [tex]29.6cm^3[/tex]

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used :

[tex]Density=\frac{Mass}{Volume}[/tex]

Given :

Mass of aluminum = 80.01 g

Density of aluminium = [tex]2.70g/cm^3[/tex]

Now put all the given values in the above formula, we get :

[tex]2.70g/cm^3=\frac{80.01g}{Volume}[/tex]

[tex]Volume=\frac{80.01g}{2.70g/cm^3}=29.6cm^3[/tex]

Therefore, the volume of aluminium sample should be [tex]29.6cm^3[/tex]