Respuesta :
Age (A) = n = 59
Age (B) = n+1 = 60
Age (C) = n+2 = 61
*The oldest is Age (C).
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n+(n+1)+(n+2)=180
n+n+1+n+2=180
3n+3=180
3(n+1)=180
n+1=60
n=59
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The answer is: 61 years old.
Age (B) = n+1 = 60
Age (C) = n+2 = 61
*The oldest is Age (C).
---------
n+(n+1)+(n+2)=180
n+n+1+n+2=180
3n+3=180
3(n+1)=180
n+1=60
n=59
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The answer is: 61 years old.
n= youngest
n+1= middle friend (by age)
n+2 = oldest
n + n + 1 + n + 2 = 180 (the sum of their ages = 180)
Combine like terms
3n + 3 = 180
Now subtract 3 from each side of the equation
3n + 3 - 3 = 180 -3
3n = 177
Now divide both sides of the equation by 3
n= 59 n + 1 = 60 and n + 2=61 Ages are 59, 60, 61
Another way 180 ÷ 3 = 60. So 60 + 60 + 60 =180 Take one from one of the 60s and add it to one of the others and you will also get 59,60 and 61.
n+1= middle friend (by age)
n+2 = oldest
n + n + 1 + n + 2 = 180 (the sum of their ages = 180)
Combine like terms
3n + 3 = 180
Now subtract 3 from each side of the equation
3n + 3 - 3 = 180 -3
3n = 177
Now divide both sides of the equation by 3
n= 59 n + 1 = 60 and n + 2=61 Ages are 59, 60, 61
Another way 180 ÷ 3 = 60. So 60 + 60 + 60 =180 Take one from one of the 60s and add it to one of the others and you will also get 59,60 and 61.